It likes *if ( (x = y) && p ) return -1;* (No, I don't have the exact st... | Hacker News

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		ctdonath on April 12, 2012 \| parent \| context \| favorite \| on: '9223372036854775807' == '9223372036854775808' It likes if ( (x = y) && p ) return -1; (No, I don't have the exact statement in question handy. It was more complicated than this example.)

jeltz on April 12, 2012 [–]

Yes, and that is because "(x == y) && p" should be written as"x == y && p" according to gcc. If you add the brackets gcc takes that as a sign that you really wanted to do an assignment.

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