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You couldn't possibly miss all 8 pieces. As soon as you make one attempt you'll get one piece.


Henrik's math calculated the chance of missing the "I love you" piece each time. The chance of missing any one other piece each time is the same.


Yes, but they're not independent. Given that you missed piece X, the probability that any one piece it's piece Y it's 1/7, not 1/8, so the chance of missing both X and Y it's lower than the product of their individual probabilities.




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